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5(7x^2-12x-4)=0
We multiply parentheses
35x^2-60x-20=0
a = 35; b = -60; c = -20;
Δ = b2-4ac
Δ = -602-4·35·(-20)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-80}{2*35}=\frac{-20}{70} =-2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+80}{2*35}=\frac{140}{70} =2 $
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